PPT Slide

Q

Q

M

M

Q

q

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M

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q

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Q

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Q

Q

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Q

q

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q

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Q

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s2 (.5)

Frequency

s2 (.2)

s2 (.2)

s2 (.1)

2st (.3)

2st (.2)

2st (.2)

2st (.3)

t2 (.1)

t2 (.2)

t2 (.2)

t2 (.4)

10

8

5

8

Average

.5*10+.2*8+.2*8+.1*5=8.7

Detection of QTL based on markers requires

Linkage Disequilibrium between marker and QTL

Relative frequency of Q must differ between marker groups

Example (arbitrary)

.1*10+.2*8+.2*8+.2*5=6.2

.3*10+.2*8+.2*8+.3*5=7.7

Average

value

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